输入Fr=17800Fa=17800 计算得:         Fr*tanα/Fa=0.839099631查表得:e=0.37221272
Jr(e)=0.2191221Ja(e)=0.244108766
根据滚动体数目输入y=
0
接触角α弧度制α
tanαcosαsinα=40=0.698131701=0.839099631=0.766044443=0.278761
将其换算为弧度制为y=
计算其最大滚动体负荷  Qmax=Fr/ZJr(e)*cosα=Fa/ZJa(e)*sinα=3534.639128
1-(1-cosY)/2e=1
任意位置滚动体负荷
Qy=Qmax[1-(1-cosy)/2*e]3/2=3534.639128
e00.10.20.30.40.50.60.70.80.911.251.672.55∞Fr*tanα/Fa10.96630.93180.60.86010.82250.78350.74270.69950.65290.60.43380.30880.1850.08310点接触Jr(e)1/z0.11560.1590.120.21170.22880.24160.25050.25590.25760.25460.220.18710.13390.07110Ja(e)1/z0.11960.17070.2110.24620.27820.30840.33740.36580.39450.42440.50440.6060.7240.85581余弦值  cosy10.9238795330.7071067810.3826834320-0.38268343-0.70710678-0.92387953-1滚动体负荷Qy3534.6391283006.5976251669.730544249.388871800000角度           y计算结果:022.54567.590112.5135157.5180Z=300